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Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 decade ago

chemistry help - balancing chemical equations?

Directions: Write correct chemical formulas for the reaction and products for the following word equations. Balance the chemical equations.

1) Iron + sulfur --> Iron(II) sulfide

Can someone help explain how to do this because i have 20 of these to do. Thank you =)

6 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    Iron (II) has a +2 charge while S is -2 so Iron (II) sulfide would be FeS.

    Fe + S --> FeS

    There shouldn't be any balancing on this one, but I'm sure the others you have will. Just remember you have to have the same amount of each element on both sides.

  • Steven
    Lv 7
    1 decade ago

    Iron is Fe, Sulfur is S, Iron (II) Sulfide is FeS

    You might think the reaction is simple - 1 atom of each:

    Fe + S -> FeS

    However, pure Sulfur likes to combine together into molecules - S8, while Iron in pure form will happily exist as individual atoms. So you'd actually need to do a larger batch:

    8Fe + S8 -> 8FeS

    Your other problems are likely to be similar.

  • Anonymous
    5 years ago

    In the water part, the coefficient 2 at the front of H(2)O to make 2H(2)O means that everything after it has 2 times that amount so 2H(2)O = 2 xH2 and 2xO = 4Hs and 2Os Change the equations to the following: 1) This is already balanced 2) 2C + 2Br(2) --> 2CBr(4) 3) 2Fe + O(2) --> 2FeO 4) This is already balanced 5) 2Si + O(2) --> SiO(2)

  • Rex
    Lv 5
    1 decade ago

    Fe + S -------- FeS

    It is balanced as is since there is 1 Fe and 1 S on each side.

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  • ?
    Lv 6
    1 decade ago

    GOOGLE THE CHEM TEAM WEB SITE FOR HELP

    Source(s): CHEM TEACHER
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