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Solve for X, and check?
√ ̅ x=x
so.. that's the question. What i did is ^2 both sides. so i got x=x^2. I dont know if it's right, please help and explain.
Thanks.
4 Answers
- MarkLv 61 decade agoFavorite Answer
You are sort of correct
x = x² is logical if x ≥ 0 (and then √x is defined)
It follows that
x - x² = 0
x(1 - x) = 0
So there are two answers:
x =0 or x = 1
- Anonymous1 decade ago
sqrt(x) = x
x = x^2
x(1 -x) = 0
==> x = 0 or 1 is the solution.
Checking: sqrt(0) = 0, so that's true
Checking: sqrt(1) = 1, so that's true
- Anonymous1 decade ago
x=1. It's the only number that is its own square root.