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More integration stuff?
The integral of (x+1)/Square root (3-2x-x^2)
I got -Square Root (-x^2-2 x+3)+c
1 Answer
- ≈ nohglfLv 71 decade agoFavorite Answer
I did a u-substitution and I got this answer
u = -x^2 -2x +3 du = -2x -2 = -1(2x + 2) = -2(x+1)
integrate -2 * du / (u)^1/2
= integrate -2 * u^-1/2 du
= 2 * integrate u^-1/2 du
= 2 * (u^1/2) / (1/2) + C
= 2 * (-x^2 -2x + 3)^1/2 + C
Check my answer and your answer by taking the derivative and see if you get (x+1)/ Square root (3-2x-x^2).
I think your answer is right.
