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Henry C
Lv 4
Henry C asked in Science & MathematicsMathematics · 1 decade ago

Math Problems i have done, need someone to check, please!?

http://hostthenpost.org/uploads/3bc5983256d0a7f97d...

I've attached a picture to make it easier for you guys!

Thanks.

2 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    Sorry, the first problem is not done properly.

    8^(- 2/3) is not the same as the square root of negative 4 !

    8^(- 2/3) = 1/[8^(2/3)] = 1/4

    so, the answer would be 1 + 1/4 = 5/4

    the second problem is substantially correct. Don't you think it would be better to express 6/2 as 3 ?

    y = 2x + 3

    QED

  • billrussell42
    Lv 7
    1 decade ago

    1 + 8^(–2/3)

    1 + [ 1 / 8^(2/3) ]

    1 + [ 1 / 64^(1/3) ]

    1 + [ 1 / 4 ]

    5/4

    you are confused about negative exponents. x^(–1) = 1/x

    y = (1/2)x – (3/2)

    multiply by 2 to clear fractions

    2y = x – 3

    swap

    2x = y –3

    y = 2x + 3

    .

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