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Question about center of mass, physics?
At one instant, the center of mass of a system of two particles is located on the x-axis at x = 2.0 m and has a velocity of 5 m/s. One of the particles is at the origin. The other particle has a mass of 0.10 kg and is at rest on the x-axis at x = 8.0 m.
What is the mass of the particle at the origin?
Calculate the total momentum of this system.
What is the velocity of the particle at the origin?
I don't have any idea how to solve this problem. Can anyone please help?
2 Answers
- Anonymous1 decade agoFavorite Answer
Let m be the mass of the particle at the origin.
The total moment of the two masses about the centre of mass is zero:
m1 * 2.0 = 0.10 * (8.0 - 2.0)
m1 = 0.30 kg.
The two particles are together equivalent to a single particle of mass 0.30 + 0.10 = 0.40 kg at the centre of mass.
The total momentum is:
0.40 * 5 = 2.00 kg m/s.
Adding the momentum of each particle gives the total momentum. If v is the required velocity:
0.3v + 0 = 2.00
v = 6.67 m/s to 3 sig. fig.
- kukwaLv 45 years ago
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