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Seal asked in Science & MathematicsChemistry · 1 decade ago

Help- science question!!!!?

In this equation 2HCl+Na2CO3=2NaCl+H2O+CO2, what is the limiting reagent and how do do you find the amount of co2 produced, given that 20ml of 2.0M Hcl is used and 5g of Na2CO3 is used?

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  • Dr.A
    Lv 7
    1 decade ago
    Favorite Answer

    moles HCl = 0.020 L x 2.0 M= 0.040

    moles Na2CO3 = 5 /106 g/mol=0.047

    the ratio between HCl and Na2CO3 is 2 : 1

    moles HCl required = 0.047 x 2 =0.094

    we have only 0.040 moles of HCl so it is the limiting reactant

    moles CO2 = 0.040 /2=0.020

    mass CO2 = 0.020 mol x 44 g/mol=0.88 g

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