Why isn't this c code working?

include<stdio.h>

#include<stdlib.h>

// replace character 'search' with 'replace' in array "text"

char * char_replace(char * text, char * search, char * replace)

{

// ans_p will point to the beginning of the "text" character array

char * ans_p = text;

// iterate through every character within "text"

// stop when "text" is pointing to a null character

while(*text != '\0')

{

// if the two characters are equal ...

if (*(ans_p) == *(search))

{

// replace the character

*(ans_p) = *(replace);

}

// increment the text pointer

*text++;

}

return ans_p;

// return the pointer to the beginning of the array

}

// main function

int main()

{

// the string to search within is text[]

// the character to look for is *search

// the character to replace *search with is *replace

char text[] = "This is part 2 of the lab", * search = "2", * replace = "3";

// print statement before, should be "This is part 2 of the lab"

printf("before:\t%s\n", text);

// perform search and replace the 3 with a 2

char * new_string = char_replace(text,search,replace);

// print out the modified statement, "This is part 3 of the lab"

printf("after:\t%s\n", new_string);

return 0;

}

When I run it it outputs the same thing rather than changing it from 2 to 3.