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At 298 K the value of Kc for the equilibrium represented by the balanced equation is 1.11 x 101. Calculate the?
At 298 K the value of Kc for the equilibrium represented by the balanced equation is 1.11 x 101. Calculate the value of Kp for the reverse reaction at the same temperature. Express answer in scientific notation.
Can somebody explain how to do this problem? Thank You
1 Answer
- 1 decade agoFavorite Answer
Ok, for the reaction forward:
A + B --> C
Kc is for the forward reaction
[C]/[A][B]
If the reaction is reversed:
C --> A + B
[A][B]/[C]
Therefore it can be stated:
Kc reverse = 1/Kc (forward)
However, since Kc and Kp are not equal to each other, the formula must be applied:
Kp = Kc/RT
Since Kc as you put it is ambiguous (it can either be 1.11x101; 1.11x10^1; etc) I will just outline the reaction you can insert the values
For simplification, I am assuming the Kc is 1.11x10^1
Rearranging the equation to solve for Kp (knowing R=8.314)
Kp=(1.11x10^1)/(8.314 x 298K)
Kp (forward) = 0.0048
Kp (reverse) = 1/Kp (forward)
=1/(0.0048)
=2.232 x 10^2
