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How do you find the base angle of an isosceles triangle?
if the exterior vertex angel is 130 degrees?
4 Answers
- ironduke8159Lv 71 decade agoFavorite Answer
If the exterior vertex angle is 130, the the vertex angle is 180 -130 = 50 degrees.
Thus the base angles total 180 -50 = 130
So eac base angle is 65 degrees
- BenLv 71 decade ago
The exterior angle of a particular angle in a triangle is equal to the sum of the other two. Call the base angle x. Since the base angles of an isosceles triangle are the same, you have:
x+x = 130
2x = 130
x = 65˚
- 1 decade ago
Vertex angles are equal, external angles are supplementary, and the base angles are equal. Cant tell you without a picture.
- Anonymous1 decade ago
n isosceles triangel ais also called an equalateral triantgle. if the sides are the same then the angles are too so its 90 degrees.
