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which molecules have the same bond order?
* Be2
*O2
*N2
*Li2
*B2
*C2
*F2
1 Answer
- Anonymous1 decade agoFavorite Answer
write molecular orbital configuration of all the species ...
Be2 = [sigma(1s)]^2 [sigma*(1s)]^2 [sigma(2s)]^2 [sigma*(2s)]^2
bond order = 1/2(2-2) = 0
O2 = [sigma(1s)]^2 [sigma*(1s)]^2 [sigma(2s)]^2 [sigma*(2s)]^2 [sigma(2pz)]^2 [pi(2px)]^2 [pi(2py)]^2 [pi*(2px)]^1[pi*(2py)]^1
bond order = 1/2(8-4) = 4/2 = 2
N2 = [sigma(1s)]^2 [sigma*(1s)]^2 [sigma(2s)]^2 [sigma*(2s)]^2 [pi(2px)]^2 [pi(2py)]^2 [sigma(2pz)]^2
bond order = 1/2(8-2) = 6/2 = 3
Li2 = [sigma(1s)]^2 [sigma*(1s)]^2 [sigma(2s)]^2
bond order = 1/2(4-2) = 2/2 = 1
B2 = [sigma(1s)]^2 [sigma*(1s)]^2 [sigma(2s)]^2 [sigma*(2s)]^2 [pi(2px)]^1 [pi(2py)]^1
bond order = 1/2(4-2) = 2/2 = 1
C2 = [sigma(1s)]^2 [sigma*(1s)]^2 [sigma(2s)]^2 [sigma*(2s)]^2 [pi(2px)]^2 [pi(2py)]^2
bond order = 1/2(6-2) = 4/2 = 2
F2 = [sigma(1s)]^2 [sigma*(1s)]^2 [sigma(2s)]^2 [sigma*(2s)]^2 [sigma(2pz)]^2 [pi(2px)]^2 [pi(2py)]^2 [pi*(2px)]^2 [pi*(2py)]^2
bond order = 1/2(8-6) = 2/2 = 1
Li2 , B2 ,F2 have same bond order i.e. 1
C2 and O2 have same bond order i.e. 2