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Statistics question, help please!?
A test for a certain disease is found to be 95% accurate meaning that it will correctly diagnose the disease in 95 out of 100 people who have the ailment. The test also 95% accurate for a negative result, meaning that it will correctly exclude the disease in 95 out of 100 people who do not have the ailment. For a certain segment of the population, the incidence of the disease is 4%.
Now suppose the incidence of the disease is 49%. Compute the probability that the person actually has the disease, given that the test is positive.
1 Answer
- dunkelblauLv 51 decade agoFavorite Answer
If we take a random population of 10000 @ 49% incidence,
Person Total Positive Negative
Sick 4900 4655 245
Healthy 5100 255 4845
Prob(Sick|Positive) for 49% incidence rate = 4655/(4655+255) = 94.8%
Now for your 4% general incidence rate
Person Total Positive Negative
Sick 400 380 20
Healthy 9600 480 9120
Prob(Sick|Positive) for 4% incidence rate = 380/(380+480) = 44.2%
There's an important point to this comparison-- when you're designing medical tests
for serious problems, the accuracy requirements tighten a lot for rarer diseases.
That 95% accuracy may sound good, but you'll end up with lots of false positives
when the incidence rate is low-- and this may cause people to ignore a positive result.