Solve each quadratic equation by factoring?

Before you can solve, you must set one side to zero.

x^2 - x - 12 = 0

Now think of factors of -12 that when added, give you -1. I'll leave that to you.

0 = x^2 + 4x + 4

Now think of factors of 4 that when added, give you 4. I'll leave that one to you also. Good luck!

a million) z^2 + 6z – 27 = 0, z^2 + 9z – 3z – 27 = 0, z(z + 9) – 3(z + 9) = 0, (x – 3)(x + 9) = 0, x = 3, or x = – 9 2) 2x^2 – 7x – 13 = 0, usimg formula x = [7 ± ?(40 9 + 104)]/4 = [7 ± ?(40 9 + 104)]/4 = (7 ± ?153) / 4, = (7 ± 3?17) / 4, 3) x^2 – 6x = 7, x^2 – 6x – 7 = 0, x^2 – 7x + x – 7 = 0, x(x – 7) + a million(x – 7) = 0, (x + a million)(x – 7) = 0, x = – a million, or x = 7 -----

x^2-x-12=0

(x+3)(x-4)

x=-3 and x=4

-x^2-4x-4=0

x^2+4x+4

(x+2)(x+2)

There is a double root at -2.