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what is the freezing pt and boling point of a solution containing 1 mole of CaCl2 in 1.00 kg of water?
kb=0.52 C/mol kf=1.86 C/mol
help??
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- Steve OLv 71 decade agoFavorite Answer
1 mole of CaCl2 in 1.00 kg releases 3 moles of ions in 1.00 kg
that's 3 molal
dT = Kf (molality)
dT = 1.86 (3)
dT = 5.58
your anser is
- 5.58 Celsius
but you might be expected to round off, based upon the number of sig figs in the "1 mole" given as data
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