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Factoring: I am lost... How do you factor 4x^3-7x^2-15x?

1 Answer

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  • 1 decade ago
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    4x^3-7x^2-15x Pull out x

    x(4x^2-7x-15) Set equal to zero

    x(4x^2-7x-15)=0

    x=0 4x^2-7x-15=0

    x=0 (4x+5)(x-3)=0

    x=0 x=-5/4 x=3

    Totally Factored =x(4x+5)(x-3)

    Source(s): Algebra Class
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