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Sarah asked in Science & MathematicsPhysics · 1 decade ago

Ten points to anyone who can help me solve this!!?

Astronomers are currently searching for planets orbiting around other stars; they have found over 400 “extrasolar" planets since the first one was discovered in 1995. In order to better understand foreign planetary systems, astronomers attempt to learn everything they can about our solar system. One of the most obvious features of our solar system is that the four inner planets are almost entirely composed of rock and metals, while the outer planets are mostly gas and ice (which is frozen gas). To explain this distribution of matter, astronomers look to the time before the

planets formed.

When our sun was first “born”, astronomers believe that it was orbited by a large disk of gas and dust that would eventually coalesce to form the planets. Before the planets formed, however, the matter in this disk would separate due to the competing forces of the gravitational pull of the sun and the outward push due to the radiation pressure of the sun’s light. To understand how these forces could cause the gas and dust to separate, assume that a dust particle is made of larger atoms and has an average density of 2500 kg/m3 and a gas particle (frozen or not) has an average density of 800 kg/m3.

Consider a particle (could be either gas or dust) of radius R and with a reflectivity coefficient of a (note that a varies from 1 to 2... totally reflective means a = 2, totally absorbent means a = 1. You will use a when you write the radiation pressure.) If this particle is at a distance r from the sun:

 Derive an expression for the inward gravitational force on the particle due to the sun, in terms of R, r, M (the mass of the sun), and r (the density of the particle).

 Derive an expression for the outward force on the particle due to the radiation pressure of the sun’s light, in terms of P (the total power output of the sun), r, R and a. (Note: be very careful when considering the area of the particle on which the radiation acts. It is NOT 2pr2.)

 Combine the two expressions to create an expression for the total force. Write the expression so that a positive total force points toward the sun.

 First two questions: what direction is the total force if R is very large? Examine the place of R in each term of the total force. What direction is the total force if R is very small?

 Set the total force to zero and solve for R. This is the radius of a particle for which the two forces are balanced. If a particle has a radius greater than this value, it should be pulled inward; if its radius is smaller than this value, it should be pushed outward.

 Using the values: M = 1.99 x 1030 kg P = 3.9 x 1026 W

Calculate the value of R for which the force is zero for:

 a gas particle for which a is 2 (we assume gas particles will be totally reflective)

 a dust particle for which a is 1 (we assume dust particles are totally absorbent)

 From your answers to the calculations, where do we expect that most of the gas in the early solar system ended up... inward or outward? Where should most of the dust ended up? Explain how your answers relate to the value of R you calculated.

3 Answers

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  • 1 decade ago
    Favorite Answer

    It starts by saying r is the distance from the sun and then it's also the density of the of the particle! Well if we change the density of the particle to 'd' then:

    Q1.

    The inward gravitational pull will follow newtons law F = G x {m1 x m2} / r^2}, Therefore, for your derivation, firstly you need to determine the mass of your particle, which is the density multiplied by the volume - d x 4/3 x piR^3:

    Then in you substitute this into the field equation, you'll get your derivation - albeit assuming the radius of particle is very small (see below for why):

    F = G x {M x d x 4/3 x piR^3} / r^2}

    F = force

    G = gravitational constant

    d = density of particle

    M = mass of sun

    r = distance between the centres of both bodies.

    Q2. - Hint only.

    Radiation will act on the hemisphere that points towards the Sun. However, as the question warns you, the area that the radiation impacts is NOT half the total surface area. This would only be correct if you squashed the particle flat, so that it was completely facing the sun. Due to the fact that the particle surface is curved, the area impacted by the radiation is actually the cross-sectional area of the particle - which is pi x r^2.

    I'm not going to do all your homework for you (you said 10 points for HELPING you solve it ;-) so you can complete the derivation for the force produced by radiation pressure - I presume you've been given a formula along the lines of F= reflective coef x radiation intensity x cross sectional area / speed of light?

    Q3 - This will follow from your derivation in Q2.

    Q4 - the gravitational force is proportional to R^3, and the force from the radiation pressure is proportional to R^2. So as R gets big, the gravitational force dominates, and when R gets small visa versa. Hint, it tells you this in Q5 anyway.

    Q5 - You can do this, just rearrange

    Q6 - You can do this.

    Q7 - You can do this.

    Q8 - You can do this.

    Q9 - You can do this.

    Good luck!

  • 1 decade ago

    If you're asking how an object is pulled apart in space, it's when the gravity on one side is a lot more then the gravity on the other side, this causes an imbalence. Will add more, have to go now

  • 1 decade ago

    Lol I gurantee no one is going to answer this

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