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How many swings of the same pendulum will it take for that process on the moon?
Suppose the time for a chemical process to take place on earth is 10.0 swings of a certain standard pendulum.
If this process takes the same amount of time on our moon, where the objects fall toward its surface with an acceleration of 1.67 m/s^2, how many swings of the same pendulum will it take for that process on the moon?
Please help! Thanks :)
1 Answer
- ronwizfrLv 71 decade agoFavorite Answer
For a simple pendulum we have that period T = 2 pi sqrt(L/g). So the number of swings is proportional to 1/T and therefore to sqrt(g). This means that the number of swings will be 10*sqrt(1.67/9.813) = 4.13.
