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? asked in Science & MathematicsPhysics · 1 decade ago

Find the Period (T), frequency (f), velocity (v), and mass (m) for this fixed standing wave? help! hw due soon?

A vibrating string 56.0 cm long is under a tension of 1.80 N. The results from five successive stroboscopic pictures are shown in the figure . The strobe rate is set at 3.60×10^4 flashes per minute, and observations reveal that the maximum displacement occurred at flashes 1 and 5, with no other maxima in between.

Heres a picture that is given: http://session.masteringphysics.com/problemAsset/1...

Question also asked for wavelength and normal mode which I got right.

wavelength = .56 m

n = 2

thanks so much!

2 Answers

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  • DH
    Lv 7
    1 decade ago
    Favorite Answer

    The time between 1 & 5 is one half of the period

    Since the strobe flashes at 3.6x10^4 per minute so the time between flashes is 60/3.6x10^4 =

    1.67x10^-3s

    Between 1 & 5 is 4 flashes which = a time of 1.67x10^-3*4 = 6.68x10^-3

    So the period is 2*6.68x10^-3 = 1.33x10^-2s

    The frequency = 1/T = 75Hz

    The wave speed = wavelength/period = 0.56m/1.33x10^-2 = 42m/s

    We have v= sqrt(T/(m/L)) so m = T*L/v^2 = 1.80N*0.56m/42^2 = 5.71x10^-4kg

  • ?
    Lv 4
    5 years ago

    A Vibrating String Mastering Physics

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