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Algebra Homework...I have been stuck for hours..HELP?
Imagine you are in the market for a new home and are interested in a housing community under construction.
A. The sales rep informs you that there are 56 houses with 2 floor plans still available. Use X to represent floor plan 1 and Y to represent floor plan 2. Write the equation that illustrates the situation.
The sales rep later indicates that there are 3 times as many homes available with the second floor plan than the first. write and equation that illustrates the situation.
Use the equations from parts A and B of this excersize as part as a system of equations. Use substitution to determine how many of each type floor plan is available. Describe the steps you used to determine how many of each type of floor plan is available. Describe the steps you used to solve the problem.
What are the intercepts of the equation from part A of this problem? What are the intercepts from part B of this problem? Where would these lines intersect if you solved the system by graphing?
Please help! I have been stuck on this for over 3 hours. :)
2 Answers
- TuriskiLv 61 decade agoFavorite Answer
First, doesn't it ever occur to you to not be stuck on a problem for 3 hours? Come to Answers after 30 minutes on the same problem, and you'll save a ton of your life. You can thank me later.
In any case.
X+Y = 56 [a]
3X = Y [b]
substituting [b] into [a]
X + (3X) = 56
4X = 56
X = 14 [x]
substituting [x] into [a]
14 + Y = 56
Y = 42
So there are 14 houses with Plan 1 and 42 houses with Plan 2.
Rewriting [a] and [b] in standard form
Y = 56 - X
Y = 3X
Remember y = mx + b where b is the y-intercept
y-intercepts
[a] (0, 56)
[b] (0, 0)
The x-intercepts are when y=0
[a] 0 = 56 - X
[b] 0 = 3X
x-intercepts
[a] (56, 0)
[b] (0,0)
They intersect at the solution X = 14, Y = 42
intersection
(14, 42)
- 1 decade ago
x + y = 56
y = 3x
if y = 3x then 3x + x = 56
x = 14 and y = 42
Cannot figure out how to make a graph. Sorry; but your coordinates are (14,42)
