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Magnetic flux between 2 Helmholtz coils?
What is the magnetic flux of a smaller coil of wire in between 2 Helmholtz coils? I know that I have to use Faraday's law so EMF = -N*(BA)/change in time. However I'm told the changing flux is caused by the angular speed of the coil, and I don't know how to relate that to Faraday's.
2 Answers
- kirchweyLv 71 decade agoFavorite Answer
Faraday's law says V = N*d(BA)/dt. If this is about a rotating coil in a magnetic field,
d(BA)/dt = BA*w, w being rotation rate in rad/s.
But your question is confusing. You don't necessarily have to use Faraday's law if all you want to know is the flux through a coil in a field. That's just BAcos(theta) where theta is the angle between the field and the normal to the coil.
