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¿Me ayudaaaaaaas =D?!!!!!?
¿Con que fuerza se atraen dos cargas q1= -20 μC y q2= 50 μC, si estan separados 20 cm?Ç
K = 9 x 10^9 m2 N/C2
2 Answers
- 1 decade agoFavorite Answer
F= f (q1 q2 ) / r^2
q1= -20 μC
q2= 50 μC
K = 9 x 10^9 m2 N/C2
r= 20cm
r=0.2m
F= (9 x 10^9 (-20x10^-6 *50x10^-6)) 0.2^2
F= 9x10^9 (-1x10^-9) / 0.04
F= -9/ 0.04 = - 225 N el signo es negativo por el sentido de la fuerza
salu2 y suerte
- Anonymous1 decade ago
ja! esta ree cagaoo
o sera porq todaviano me enseñan eso?
xD
