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how do i solve (cot Θ)(sec Θ)?

im trying to solve it but i dont know if its right.

3 Answers

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  • 1 decade ago

    Cotx = Cosx/sinx

    Secx = 1/cosx

    (Cotx)(secx)=(Cosx/Sinx)(1/Cosx)

    The Cosx can be cancelled ang you are left with 1/sinx

    =cscx

  • 1 decade ago

    (cos/sin)(1/cos)= cross out the cosines= 1/sinΘ= cscΘ

    Source(s): Knowledge
  • 1 decade ago

    cos/sin * 1/cos

    = 1/sin= csc

    Source(s): Trig
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