Please help on Algebra.?

Width—w:

2(w + w + 3) = 26

2w + 3 = 13

2w = 10

w = 5

Length:

= 5 + 3

= 8

Answer: width, 5 inches; length, 8 inches

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Length—x:

2(x + 1/3[x - 3]) = 70

x + 1/3x - 1 = 35

3x + x - 3 = 105

4x = 108

x = 27

Width:

= 1/3(27 - 3)

= 1/3(24)

= 8

Answer: length, 27 inches; width, 8 inches

hey this isn't so bad ok let's start with what you know

the length of a rectangle is 3 inches more than width so you can write that as l=w+3,

and obviously, a rectangle has two lengths and two widths. so that would be 2(w+3)+w+w=26. t

he 2(w+3) is the two lengths and the "w"s are the widths.

let's simplify. 2(w+3)+w+w=26 is also 4w+6=26. that's simplifying the equation.

which i won't get into...then you solve it. 4w+6(-6)=26(-6) >> (5divide)4w=20(divided by 5) >> w=5

then you go back to l=w+3 and input your newfound number for w. l=5+3,

aka L=8 and W=5

the other one is pretty much the same as the first,

these two are very similar, so I'll help you with the first and it also applies to the second. for the first one, you would label the width as x and the length as x+3. the perimeter is 2l+2w, so put in the x values for the perimeter. you would get 2(x+3)+2(x)=26, or 2x+6+2x=26. solving for x you would have 4x=20, and x=5, which we already said that the width was x, so the width is 5, and the length would be 8. do the same things for the second one. hope this helps

1. 2(w+3) + 2w = 26

w= 5

L= 8

2. 2(3w+3) + 2w = 70

w= 8

L=27