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jeff
Lv 4
jeff asked in Education & ReferenceHomework Help · 1 decade ago

Need help on Algebra word problem?

Kelly has a collections of dimes, nickels and quarters with a total value of $10.80. There are nine more nickels than dimes and twice as many quarter as nickels. How many of each coin in her collection?

Nickels_______

Dimes_______

Quarters______

1 Answer

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  • 1 decade ago
    Favorite Answer

    No. of nickels—n:

    5n + 10(n - 9) + 25(2n) = 1,080

    n + 2(n - 9) + 5(2n) = 216

    n + 2n - 18 + 10n = 216

    13n = 234

    n = 18

    No. of dimes:

    = 18 - 9

    = 9

    No. of quarters:

    = 2(18)

    = 36

    Answer: nickels, 18; dimes, 9 & quarters, 36

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