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Physics homework help vectors numerical problem?
if a vector B is added to vector A the result is 6i^+1j^ .if B is subtracted from A ,the result is -4i^+7j^.what is the magnitude of vector A?
if i can get a detailed solution to this problem!
3 Answers
- 1 decade agoFavorite Answer
B + A = (6i + j)......1
A - B = (-4i + 7j)......2
From 2, B = A + 4i - 7j
Putting B In 1
A + 4i - 7j + A = (6i + j)
2A = 2i + 8j
A = (2i +8j)/2 = (i + 4j)
- Dr. FellLv 51 decade ago
B + A = 6i^ + 1j^ (1)
A - B = -4i^ + 7j^ (2)
B = 4i^ - 7j^ + A
plug this into equation 1
4i^ + 7j^ + A + A = 6i^ + 1j^
2A = 2i^ + 8j^
A = i^ + 4j^
- ?Lv 45 years ago
a - acceleration m - mass F - stress v - velocity t- time M - momentum a million. F = m*a = 3*seventy six = 228 2. do no longer undergo in strategies 3. F = m*(v/t) => 272 = 0.0.5*(50/t) => t = 0.01 sec 4. M = m*v => dM/dt = m*dv/dt => dM/dt = m*a = 0 (in view that a is 0, dv/dt that's value of exchange of velocity with time is acceleration) for this reason there is not any exchange in momentum with time.
