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physics problem involving initial velocity vector and constant acceleration vector, need to find time?
v(initial)=11i+14j
a=-1.2i+.26j
Need to find the time where this crosses back over the y axis, but don't know what formula to use.
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- 1 decade agoFavorite Answer
v(final) = v(initial) + a*t
v(final) = (11i + 14j) + (-1.2i + 0.26j)t
= (11 - 1.2t)i + (14 + 0.26j) t
Where this crosses the y-axis, the i-component will be zero.
11 - 1.2t = 0
t = 11/1.2 = 9.17 s
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