F Leah is 6 years older than Sue, and John is 5 years older than Leah, please read whole question.....?

Question

If Leah is 6 years older than Sue, and John is 5 years older than Leah, and the total of their ages is 41. Then how old is Sue? 
A. 8 
B. 10 C. 14 D. 19 E. 21 
I did the equation (6+x) + (5+6+x) = 41 and came up with 12 which i was able to prove ( (6+x)+(5+6+x) =? 41 (when i did the equation with x as 12, 41 equalled 41). But it's not one of the answers pls help.

Anonymous · Accepted Answer

shes 8

Leah is 14
John is 19

adds up to 41

theres your math right there

x+(x+6)+(x+11)

? · Answer

L= Leah S= Sue J= John when you consider that Leah is 6 years older than Sue, L= 6+S and John is 5 years older than Leah's age (6+S) J=5+(6+S) =11+S S+J+L=40-one Sub "J=11+S" and "L= 6+S" into J and L: S+(11+S)+(6+S)=40-one Simplify: 3S+17=40-one Subtract 17 from the two factors: 3S=24 Divide the two factors with the aid of 3: S=8 Sue is 8!

Stephen C · Answer

the answer is C. 14
let leah = x
therefore sue = x-6 
and john is x+5
the total of their ages is x+x-6+x+5=41 
this simplifies to 3x-1 =41
3x=41+1
3x=42
x=42/3
x=14

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F Leah is 6 years older than Sue, and John is 5 years older than Leah, please read whole question.....?

3 Answers