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Find the zeros of each function x3 + 2x2 + 3x + 4 and this function–x4 + x3 + 7x2 – x – 6?
PLease help my brain is frozen thanks
i know the ^ sign I was in a hurry thank you very much!! and I am sorry if this ? offened you. I had a mental nlock on these two questions... I really did not expect yahoo to give me the answer, but was amazed by the ignorance from you nevershoutnever. I can only pray for you and that you never need help!!
3 Answers
- 1 decade agoFavorite Answer
The first has only one real root at -1.65.
The second has four real roots at -2, -1, 1, 3.
Source(s): http://www.wolframalpha.com/ - Anonymous4 years ago
you opt for each little thing on the LS to have a effortless denominator. Multiply via styles of one million. (6/6) * (8/x) + (2/2) * ( (x+6) / 3x) + (x-4)/6x = 8/9 40 8/6x + (2x+12)/6x + (x-4)/6x = 8/9 (40 8 + 2x + 12 + x - 4) / 6x = 8/9 (3x + fifty six) / 6x = 8/9 go multiply 9 (3x + fifty six) = 8 (6x) 27x + 504 = 48x 504 = 48x - 27x 504 = 21x x = 24
- Anonymous1 decade ago
Do your own home work missy! xD
But, just to let you know, if it's exponent you're trying to show, use this --> ^ <-- before the number (ex: x^6 that is x to the power of 6)
