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Freezing point question?
What is the freezing point in degrees Celsius of a solution of 15.7 g of LiCl in 136 g of water, assuming complete dissociation? For water K= -1.86 degrees Celsium kg/mole. I need to know how to set up the problem as well as how to solve it. Thank you.
1 Answer
- pisgahchemistLv 71 decade agoFavorite Answer
The you need to read more about "colligative properties", and in particular, "freezing point depression".
Any nonvolatile solvent that you dissolve in water will lower the freezing point and elevate the boiling point.
DT = (i)(Kf)(m) .... i = van't Hoff factor - comes from the number of particles in solution from 1 molecule of the solvent, Kf is the freezing point depression constant, m = molality, the concentratin of the solute in moles per kg of solvent
DT = (2)(1.86C/m)(0.136 kg) = 0.506C
The freezing point will be lowered to -0.506C.