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The magnitude of the one-dimensional momentum of a 2 kg particle obeys the relationship p=2t + 3. What was the?
The magnitude of the one-dimensional momentum of a 2 kg particle obeys the relationship p=2t + 3. What was the average force applied to the particle from t=1 second to t=3 seconds?
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- Anonymous1 decade agoFavorite Answer
ave force = change in momentun/ change in time
=9-5/3-1
=2N
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