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Redox Stoichiometry HELP!!!!!!!!!?
so i performed a total of 3 trials twice.
T1
the final buret was 17
initial was 4.3
volume of KMnO4 is 12.7
T2
the final buret was 29.5
initial was 17
volume of KMnO4 is 12.5
T3
the final buret was 42
initial was 30.5
volume of KMnO4 is 12.5
AVG IS 12.6
PART B
the final buret was 25.5
initial was 14.5
volume of KMnO4 is 11
T2
the final buret was 36.5
initial was 25.5
volume of KMnO4 is 11
T3
the final buret was 47.5
initial was 36.5
volume of KMnO4 is 11
Calculate the concentration of potassium permanganate. I don't understand this at all!
I so far have the equation .. of
OA: MnO4 + 8H + 5e -> Mn2+ + 4H2O
SA: Fe2+ -> Fe 3+ + e-
net: MnO4 + 8H + 5Fe -> Mn2+ + 4H2O + 5Fe
and i dont know where to go from there .
1 Answer
- 1 decade agoFavorite Answer
To know the conc of KMnO4 you need to tell vol of Fe++ and normality of Fe++ then only you can solve the problem by using
N1V1=N2V2 and Conc =eq.wt x Normality