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Physics help please??????????
An object is launched from the origin with a velocity of 15.0 m/s at an angle of 45.0 degrees above the horizontal. What is the velocity of the object 2.00 seconds later?
2 Answers
- 1 decade agoFavorite Answer
Let's say that the velocity of the object according to the x axis is Vx, and according to th Y axis is Vy.
At the beginning Vx=Vy=15*sqrt(2)/2 due to the fact that the angle is 45 degrees.(Vx=Vcos(angle),Vy=Vsin(angle))
Note that Vx remains constant as no force acts on the X axis. Vy changes according to the following formula:
V=Vy-g*t
At 2 seconds V will be -9.045 m/s(minus sign indicates the object is moving downwards). The final velocity is sqrt(V^2+Vx^2) which is app. 14 m/s.
Source(s): Physics textbook - 1 decade ago
wooo! physics! is that the question in your test? assuming its a test question? i will assume there is earth gravity (correct if wrong), at want point is it travelling at 15m/s? as far as i am aware to calculate the speed at 2s it would probably be easyest to work at out the acceleration. for this you need the force on it, and the mass of the object.
tell me exactly what the question states, or tell me your situation, or tell what understanding you are trying to achieve.