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If you spin the wheel 3 times, what's the probability that it will land on 70% the first 2 times?
A spin wheel is marked with a 30% portion and a 70% portion. what is the probability that it will land on 70% the first two times out of 3 spins?
5 Answers
- NoneLv 71 decade agoFavorite Answer
The probability of landing on the 70% area in any spin is 0.7. The probability of two such spins following each other is 0.7 x 0.7 = 0.49. The third spin does not matter
All the probabilities for the first two spins are:
P(70,70) = 0.49
P(70,30) = 0.21
P(30,70) = 0.21
P(30,30) = 0.09
Add them together and you get P(all) = 1.0, an unsurprising outcome
- 1 decade ago
the 1st time it landed on 70% .'. probability is 1/2
the 2nd time it landed on 70% .'. probability is 1/2
the 3rd time it landed on any portion.'. probability is 2/2
so 1/2x1/2x2/2=1/4
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