How fast would someone of six foot one inch height fall?

Let's ignore your ridiculous pretense, and assume that the person fell from ten feet. Until you approach terminal velocity (about 120-200 mph depending on position), weight and height are irrelevant. An object falling from ten feet will accelerate at 9.8m/s^2, just like everything else, and will be going about 13 mph when it hits. Whether that causes damage depends on a huge number of other things.

What do you mean by "ignoring gravity rules"? Gravity is entirely the reason why objects fall if not constrained by a support.

And...height is irrelevant...and to most extent, weight is irrelevant, since it is also proportional to inertia.

Objects falling do not do so at constant speed. Otherwise you could jump off a skyscraper just as safely as you could jump off of a table.

Answer --> 25.4 fps (feet per second)

Weight and the person's height don't matter at all. Given:

m = 165 lbs (doesn't matter, but I'll put it here)

h = 6'1" (doesn't matter, but I'll put it here)

H = 10 ft

g= 32.15 ft/s^2 (Earth gravity)

t = unknown time to fall

First -- use SI units from now on.

Second -- determine the time it takes to fall

Tf = SQRT { [2H] / g }

Tf = SQRT { [2 * (10 ft)] / [32.15 ft/s^2] }

Tf = SQRT { [ 20 ft ] / [ 32.15 ft/s^2 ] }

Tf = SQRT { 0.622 s^2 }

Tf = 0.789 s

Third -- find the velocity at impact

Vf = Vi + at

Vi = 0.0 m/s

a = gravity

t = what you just found

Vf = (0.0 m/s) + [ (32.15 ft/s^2) * (0.789 s) ]

Vf = 25.4 ft/s