find lim x approaches 3+ absolute value of 6-2x/2x-6,?

Question

lim x-0  tan(3x)/x, evaluate this limit, if it doesn't exist, explain

lim x-0   sin x-tan x/sin^3 x, evaluate this limit, if it doesn't exist, explain.

let f(x)=x^2   x<- 0
           x^3+1  x>0  determine whether f is continuous at 0.  If not classify the discontinuity as removable, jump or infinite.  Help is needed,  please...

vect · Accepted Answer

/////////////
find lim x approaches 3+ absolute value of 6-2x/2x-6,?
-1

gaisford · Answer

l4-xl = l x-4 l = (x-4) sign (x-4) Dont ignore that, once you're calculating the lim of a function for x->4, you're working in an area from 4, yet no longer precisely in 4. So, sign (x-4) =a million is x is larger than 4 and -a million if x is decrease than 4. lim (x-4)^3/[(x-4) sign(x-4)] = lim (x-4)^2/sign(x-4) If x has a tendency to 4-, then the decrease is 0+ divided by potential of -a million, so the consequence is 0-. If x has a tendency to 4+, the consequence is 0+ So, the consequence is 0 interior the 2d case, x/lxl is a million/sign (x) = sign (x), when you consider that a million/a million is a million and a million / (-a million) is -a million So, the consequence is sin x by potential of sign x. sin x has a tendency to 0, so the consequence would be 0. Ana

Trending News

find lim x approaches 3+ absolute value of 6-2x/2x-6,?

2 Answers