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Trying to figure what the scale is on a photo(measurement)?
I have a photo of a whitetail deer. I know the average size of a deers ear is 6.5 inches long. In the photo, the ear measures 3/8 inches, and measuring one of his tines on his antler it is 13/16 inches in the photo. How do I determine the actual size of this tine with this info? What is the "scale" or how do I set up the math to figure this out?
Thanks
1 Answer
- MathMan TGLv 71 decade agoFavorite Answer
Simple division:
6.5 = 52/8
52/8 on the deer = 3/8 on the picture,
so the scale is 52 : 3 (or 3 : 52)
13/16 * 52 / 3 = 676 / 48 = 14.08 inches
Another way to check:
tine / ear should be the same in both
tine / ear = (13/16) / (3/8)
tine = 13 * 8 / 16 * 3 = 104 / 48 = 2.16667 times the ear.
That times 6.5 = 14.08
Two things to keep in mind:
1)
Even if the average ear is 6.5 inches,
this one could be 6.25 or 6.6 or what have you.
Every deer will have a slightly different size ear.
So your estimate should be in a range, not a specific number.
2)
Since you are multiplying by 52/3 (around 17),
whatever error you make in measuring on the photo
is magnified by a factor of 17.
So if you are off by 1/16" on the photo measurement,
you'll be off by about 1" on the actual size.
The accuracy of the estimate you need will determine
how carefully you make the measurements on the photo.