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A solution of benzene in the solvent tetrahydrofuran has a mole fraction of C6H6 of 0.293.?
A solution of benzene in the solvent tetrahydrofuran has a mole fraction of C6H6 of 0.293. What mass (g) of the solution must be taken if 2220 g of benzene is needed?
other helpful information:
Molar Mass (g/mol)
C6H6 78.12
C4H8O 72.12
Density (kg/m3):
C6H6 878.6
C4H8O 889.2
Name/Formula:
benzene
C6H6
tetrahydrofuran
C4H8O
any help is appreciated. i'm really lost on how to solve this problem.
1 Answer
- Anonymous1 decade agoFavorite Answer
You can rewrite the mole fraction as:
(0.293 moles C6H6)/(0.707 moles THF)
Now with this conversion we can determine the amount of THF present in solution:
(2220 g C6H6) x [(1 mole C6H6)/(78.12 g)] x [(0.707 moles THF)/(0.293 moles C6H6)] x [(72.12 g THF)/(1 mole THF)] = 4945 g THF
Therefore, the mass of the solution is (2220 g + 4945 g) = 7165 g solution.
Cheers.