Simple net torque problem in Physics?

Okay. So what you need to do is find the net torque.

So the clockwise torque:

The force acting perpendicularly to the beam is given by 8sin40

The radius is 0.25m (You have to write it in metres because the torque has units of Newton metres)

So, the net CW moment is 0.25*8sin40 = 1.28 Nm

The anticlockwise torque:

The force acting perpendicularly to the beam is given by 10sin30

The radius is 0.75m

So the net ACW torque is 0.75*10sin30 = 3.75Nm

So, the net torque is 3.75Nm ACW + 1.28Nm CW

=3.75Nm ACW - 1.28Nm ACW

=2.464 Nm ACW

Since on that screenshot it says 2 significant figures, the answer would in fact be 2.5Nm