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¿Hallar la ecuacion de la recta que pasa por el puntoA(6,8) y es perpendicular a la recta 4x+y+4=0?
AYUDA COMO LO RESUELVO
2 Answers
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- Anonymous1 decade agoFavorite Answer
la recta 4x+y+4=0
corta a x en (-1,0) , a y en (0,-4)
su pendiente es m=(y₂-y₁)/(x₂-x₁)
m=-4/1 =-4
la perpendicular tiene pendiente de m₂= -1/m₁
m₂=1/4
si pasa por el punto (6,8)
para la ecuación usas y-y₁=m(x-x₁)
y-8=1/4(x-6)
y-8=x/4-6/4
4y-32=x-6
-x+4y-26=0
- Graciela MLv 61 decade ago
Reemplazas los valores de X e Y
Y = a.X + b
8 = 4.6 + b
8 - 24 = B
- 16 = b
La Ecuación queda:
Y = - 1/4 X - 16
Suerte!!!
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