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HELP ME SOLVE THESE, SIMPLE FACTORING! MATH (NO SOLUTION)?
Factor the following and solve the roots of the equation. (no solution needed)
4x²-2x=0
x²-2x-15=0
3x²-4x-4=0
2 Answers
- 1 decade agoFavorite Answer
1.) 4x^2-2x=0
2x(2x-1)=0
2x=0 2x-1=0
no 2x=1
x=.5
2.) can not be factored
3.) 3x^2-4x-4=0
(3x+2)(x-2)=0
3x+2=0 x-2=0
3x=-2 x=2
x=-2/3
check all answers
- 4 years ago
First, that isn't an equation. What you need to do is to decompose that expression into some factors. you have x^8 + 8 x^2 = x^2(x^6+8) = x^2((x^2)^3 + 2^3). you should be attentive to that a^3 + b^3 = (a+b)(a^2-ab+b^2), so your expression will become: x^8 + 8x^2 = x^2(x^2+2)(X^4 - 2x + 4). i assume you purely did no longer be attentive to the formula.
