If one leg measures 6cm and the hypotenuse is 10cm, find the other leg of the triangle. MATH PROBLEM?

ok well u need to know the Pythagreon Theorem which is a^2+b^2=c^2

c^2 is always the hypotenuse

so your equation is 10^2=6^2+b^2

100=36+b^2

subtract 36 from both sides

64=b^2

square root each side

8=b so your other leg is 8 cm

Just use the Pythagoream theorem of a^2+b^2=c^2 (a and b being each leg, and c being the hypotenuse.)

6^2+x^2=10^2

36+x^2=100

x^2=64

x=8

The other leg is 8 cm

6^2+b^2=10^2

36+b^2=100

b^2=64

b=8

The other leg of the triangle is 8 cm.

let the unknown side be x.

then using pythagoras theorem,

x^2 + 6^2 = 10^2

x^2 = 64

x = 8

10^2 - 6^2 = answer^2

100 - 36 = answer^2

64 = answer^2

answer = square root (64)

answer = 8