Can you solve this using Quadratic Formula? PLS HELP! MATH PROBLEM?

a = 3

b = -4

c = 1

hence,

x = (4 ± √16-12)/6

x = (4 ± 2)/6

x = (4+2)/6 or x = (4-2)/6

x = 1 or x = 1/3

3x^2 -4x +1 = 0 (ax^2 + bx + c =0)

x = -(4) ± √(-4)^2 - 4(3)(1)

¯¯¯¯¯2(3)¯¯¯¯¯¯

-4 ± √(16) -12

¯¯¯¯¯6¯¯¯¯¯¯

-4 ± 2

¯¯¯¯¯6¯¯¯¯¯¯

Answer -4 + 2 = -2/6 = -1/3

Answer -4 - 2 = -6/6 = -1

Roots of -1/3 and -1

0 = 3x² - 4x + 1

x = [ -b ± √ ( (b)² - 4(a)(c) ) ] / 2(a)

x = [ -(-4) ± √ ( (-4)² - 4(3)(1) ) ] / 2(3)

x = [ 4 ± √ ( 16 - 12 ) ] / 6

x = [ 4 ± √4 ] / 6

x = [ 4 ± 2 ] / 6

x = (4 - 2) / 6 or (4 + 2) / 6

x = { 1/3, 1 }