uring a baseball game, a batter hits a popup to a fielder 73m away?

I get 10.6 s for the horizontal velocity, but close enough.

but to find the height, we recognize that the time of flight is determined by the time it takes gravity to cause the ball to accelerate to the surface

if the total flight time is 6.9s, the time to maximum height is half of that or 3.45s

then, the ball is dropping from this height, and we know that

h= 1/2 gt^2 = 1/2*9.8m/s/s*(3.45s)^2

h=58.3m

Time of Flight = 6 sec Time to top = 6 ? 2 = 3 sec ?Vy? = g?•?t?+?Vyi??...??vertical velocity at top = Vy? = 0 ???0 = (-9.8)?•?(3)?+?Vyi ???Vyi = 29.4 m/sec??...??preliminary vertical velocity factor ??????Dy = (½)?•?g?•?t²?+?(Vyi)?•?t ??????Dy = (½)?•?(-9.8)?•?(3)²?+?(29.4)?•?(3) ??????Dy = 40 4.a million meters top top