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Zikro
Lv 5
Variable based inverses?
Show that, for every value of a, the function
f(x) = a + (1/(x − a))
is its own inverse.
???
1 Answer
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- TuriskiLv 61 decade agoFavorite Answer
g(x) = f^-1(x)
= a + (1/(x − a))
f(g(x)) = a + 1/(a + 1/(x − a) − a)
= a + 1/(a-a + 1/(x-a))
= a + 1/(1/(x-a))
= a + (x-a) = x
And clearly, because g(x) = f(x)
g(f(x)) = f(g(x))
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