Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
a mouse has a constant speed 2m/s. after 20s, a cat moves with acceleration 4m/(s^2).?
Find the time when cat catch mouse
1 Answer
- bonoboLv 71 decade agoFavorite Answer
Dм = mouse's displacement (distance traveled).
Dc = cat's displacement
Vм = mouse's velocity (constant) = 2 m/sec ... (assumed zero at t = 0)
Vci = cat's initial velocity = 0
Ac = cat's acceleration = 4 m/sec² ... (at t = 20 sec)
Tc = cat's motion time frame relative to mouse's (t)
Tc = t − 20
******* "t" must be ≥ 20 sec
_________________________________________________
Dм = (Vм) • t
Dм = (2) • t
Dc = (½) • (Ac) • (Tc)² + (Vci) • (Tc)
Dc = (½) • (4) • (t − 20)² + (Vci) • (t − 20)
Dc = (½) • (4) • (t − 20)²
Dм = Dc
2t = 2(t − 20)²
t = t² − 40t + 400
0 = t² − 41t + 400
________________
t = { 41 ± √ [ (-41)² − 4(1)(400) ] } ⁄ 2(1)
t = { 41 ± 9 } ⁄ 2
t = 16 sec (disregard) and t = 25 sec
t = 25 sec from when the mouse starts since ******* "t" must be ≥ 20 sec