Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
What is the difference in concentration of 0.200 M Cu(NO3)2 with different amount of water?
hey i am a bit confuse with the concentration.
I have 10mL of 0.200M Cu(NO3)2 with 0 ml H2O. so i guess the concentration of Cu(NO3)2 is 0.200M
but if i have 8mL of 0.200M Cu(NO3)2 with 2 mL of H2O. What will be the concentration of Cu(NO3)2?
I am guessing the concentration should be less since we are adding water. but i cannot find a way to calculate it. Thanks for any advices.
1 Answer
- Anonymous1 decade agoFavorite Answer
The initial concentration of your solution is 0.200 M. The concentration of the solution after dilution can be found by using the following equation:
C1V1 = C2V2
where C stands for the concentration and V is the final volume of the solution. So, let's find out what the concentration is after adding 2mL to 8mL of the 0.200 M solution:
C2 = C1(V1/V2)
C2 = (0.200 M)(8mL/10mL) = 0.160 M
Cheers.