3y+3(1-y)-y=6...whats y?

3y+3(1-y)-y=6

Reorder the polynomial 1-y alphabetically from left to right, starting with the highest order term.

3y+3(-y+1)-y=6

Multiply 3 by each term inside the parentheses.

3y+(-3y+3)-y=6

Since 3y and -3y are like terms, add -3y to 3y to get 0.

0+3-y=6

Combine all similar terms in the polynomial 3y-3y+3-y.

3-y=6

Reorder the polynomial 3-y alphabetically from left to right, starting with the highest order term.

-y+3=6

Since 3 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 3 from both sides.

-y=-3+6

Add 6 to -3 to get 3.

-y=3

Multiply each term in the equation by -1.

-y*-1=3*-1

Multiply -y by -1 to get y.

y=3*-1

Multiply 3 by -1 to get -3.

y=-3

First distribute the 3 into the parentheses. That's multiplying by both terms in the parentheses.

3y + 3 (1-y) - y = 6

3y + 3 - 3y -y = 6

Then combine like terms (everything with y).

-1y + 3 = 6

Then subtract 3 from both sides.

-1y = 3

Then divide by -1 to get y alone.

y = -3

y= -3

First distribute 3 to 1-y

3y+3-3y-y=6

Then combine all the y's

-y+3=6

Then subtract 3 from both sides

-y=3

Then divide both sides by -1

y=-3

-3=y

Just isolate y.