How would you add this rational expression?

ok, for the first one just find a common denominator as you always would when adding such fractions. In this case the common denominator is 7(n-2) so you want to alter both fractions so that they have that base. Your are going to have to multiply each side by a different form of 1. multiply the whole left side by 7/7 (which is still just 1) and similarly, multiply the right side by n-2/n-2

this gives you 7 / [7(n-2)] + n(n-2) / [7(n-2)] since the bases are the same, just add the numerators and put them both on that one base.

Your final answer is (7+ n(n-2)) / [7(n-2)]

for the second one you can factor out a 2x from the numerator which gives you as a numerator 2x(4x-2) since there is a 2x in the denominator just cancel them and you are left with 4x-2!

I hope that helped ;)

so long because the denominators are equivalent, you are able to combine words interior the numerator. it is an similar as once you're dealing with fractions. 2/3 + 2/3 = (2+2)/3 = 4/3 2x/3 + 2/3 = (2x+2)/3 7x/3 + x/3 = 8x/3 So, #a million is 9x/13 and #2 is 9x/15, which could be decreased to 3x/5.