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physics question???please help?

could a vector ever be shorter than its components...why?

2 Answers

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  • 1 decade ago
    Favorite Answer

    F = vector

    F cos x

    F sin x

    are components for any angle

    since sine and cosine are fractions LESS THAN ONE, components are always shorter than the vector

    [x = 0 or 90, component = vector]

    sine = perpendicular/hypotenuse

    cosine = base/hypotenuse

    hypotenuse > perpendicular or base

  • Anonymous
    1 decade ago

    No. Pathagorean theorem states a^2 + b^2 = c^2.

    Since a vector's components always make a right triangle, that always applies.

    a^2 + b^2 > c^2 is never true.

    Source(s): Old, dead physics minds.
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