An equation of a line and the coordinates of a point?

first satisfy the given equation within the mod..... then divide by the square root of the sum of the squares of coefficients of x and y

[] : mod

d : perpendicular distance

then

d = [ Ax + By + C ] / ( A^2 + B^2 )^1/2

for this question ,

x = -a , y= -a A = 3 , B = -4 , C = 8

therefore substitute the values

d = [ 3 (-a ) + (-4)(-a) + 8 ] / ( 3^2 + ( -4 )^2 )^1/2

d= [ -3a + 4a + 8 ] / 5

d= [a + 8 ] / 5

it is the answer ....... substitute the x if the answer ( a +8 ) is less than 0 then put it as positive because [ - k ] = k

hope this helps..........

perpendicular distance of Point (a,b) from the line lx + my + c =0 is given by the formula ;;;

L = (al +bm +c ) /root( l^2 +m^2) therefore in the give equation

L = ( --3 a---4a +8) / root (3^2 +4^2) or length = (--7a +8)/5 ans