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buat sobat @mukti tolong jawab secepatnya coz penting....?

oh iya tentang pertanyaanku yg barusan http://id.answers.yahoo.com/question/index;_ylt=Ap...

sob tolong jawab yg no 2 ya sob itu yg frekuensi roda 1 bener 300rpm nanti dijadikan hz sob jd mungkin harus di bagi kan 1rpm=1/60hz please jwb no 2 ya

1 Answer

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  • Mukti
    Lv 7
    1 decade ago
    Favorite Answer

    2).

    mungkin yang anda maksud 300 rpm adalah kecepatan sudutnya, karena rpm adalah satuan kecepatan sudut sedangkan satuan frekuensi adalah Hz

    ω1 = 300 rpm = 300/60 rps = 5 rps = 5x 2π rad/s = 10π rad/s

    Roda saling bersinggungan, kecepatan linearnya sama

    v1 = v2

    ω1 r1 = ω2 r2

    10π x 0,08 = ω2 x 0,12

    ω2 = 7,5π rad/s

    a. frekuensi roda 2 :

    ω2 = 2π f

    7,5π = 2π f

    f = 3,75 Hz

    b. banyak gigi roda2 : banyak gigi roda1 = ω1 : ω2

    banyak gigi roda2 : 30 = 10 : 7,5

    banyak gigi roda 2 = 4/3 x 30 = 40

    tambahan:

    rpm itu bukan satuan frekuensi boss, dan kalau mengkonversi rpm ke frekuensi bukan dibagi 60.

    300 rpm = 300/60 rps = 5 rps = 5x2π rad/s = 10π rad/s

    ω = 2π f

    10π = 2π f

    f = 5 Hz

    jadi frekuensi roda2 = 5Hz

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